Though that's seems intuitively correct, I'm not sure
in reality it's true because the curvature is much
less than a wavelength. I would think that the
surface would look essentially flat to a 1420 MHz
I need to reread my physics notes on this subject,
> Suppose you used half a ping-pong ball for each? The
> aluminized surface would be the flat part of the
> sphere, which would be parallel to the surface of the
> water, when the water was at rest. However, even
> wouldn't work as you went up the sides of the curve.
> Each ping-pong ball's flat surface would be pointing
> more or less straight up. (And that's assuming it
> didn't decide to flop over.)
If you were to use half spheres, the flat side ought
to be parallel to the surface of the water...
remember that its "gravity" vector is now at an angle
other than straight up and down due to the centripetal
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